Optimal. Leaf size=229 \[ -\frac {2 a^2 \left (A \left (8 n^2+30 n+25\right )+2 B \left (4 n^2+13 n+9\right )\right ) \cos (e+f x) \sin ^{-n}(e+f x) (d \sin (e+f x))^n \, _2F_1\left (\frac {1}{2},-n;\frac {3}{2};1-\sin (e+f x)\right )}{f (2 n+3) (2 n+5) \sqrt {a \sin (e+f x)+a}}-\frac {2 a^2 (A (2 n+5)+2 B (n+3)) \cos (e+f x) (d \sin (e+f x))^{n+1}}{d f (2 n+3) (2 n+5) \sqrt {a \sin (e+f x)+a}}-\frac {2 a B \cos (e+f x) \sqrt {a \sin (e+f x)+a} (d \sin (e+f x))^{n+1}}{d f (2 n+5)} \]
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Rubi [A] time = 0.49, antiderivative size = 229, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {2976, 2981, 2776, 67, 65} \[ -\frac {2 a^2 \left (A \left (8 n^2+30 n+25\right )+2 B \left (4 n^2+13 n+9\right )\right ) \cos (e+f x) \sin ^{-n}(e+f x) (d \sin (e+f x))^n \, _2F_1\left (\frac {1}{2},-n;\frac {3}{2};1-\sin (e+f x)\right )}{f (2 n+3) (2 n+5) \sqrt {a \sin (e+f x)+a}}-\frac {2 a^2 (A (2 n+5)+2 B (n+3)) \cos (e+f x) (d \sin (e+f x))^{n+1}}{d f (2 n+3) (2 n+5) \sqrt {a \sin (e+f x)+a}}-\frac {2 a B \cos (e+f x) \sqrt {a \sin (e+f x)+a} (d \sin (e+f x))^{n+1}}{d f (2 n+5)} \]
Antiderivative was successfully verified.
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Rule 65
Rule 67
Rule 2776
Rule 2976
Rule 2981
Rubi steps
\begin {align*} \int (d \sin (e+f x))^n (a+a \sin (e+f x))^{3/2} (A+B \sin (e+f x)) \, dx &=-\frac {2 a B \cos (e+f x) (d \sin (e+f x))^{1+n} \sqrt {a+a \sin (e+f x)}}{d f (5+2 n)}+\frac {2 \int (d \sin (e+f x))^n \sqrt {a+a \sin (e+f x)} \left (\frac {1}{2} a d \left (2 B (1+n)+2 A \left (\frac {5}{2}+n\right )\right )+\frac {1}{2} a d (2 B (3+n)+A (5+2 n)) \sin (e+f x)\right ) \, dx}{d (5+2 n)}\\ &=-\frac {2 a^2 (2 B (3+n)+A (5+2 n)) \cos (e+f x) (d \sin (e+f x))^{1+n}}{d f (3+2 n) (5+2 n) \sqrt {a+a \sin (e+f x)}}-\frac {2 a B \cos (e+f x) (d \sin (e+f x))^{1+n} \sqrt {a+a \sin (e+f x)}}{d f (5+2 n)}+\frac {\left (a \left (2 B \left (9+13 n+4 n^2\right )+A \left (25+30 n+8 n^2\right )\right )\right ) \int (d \sin (e+f x))^n \sqrt {a+a \sin (e+f x)} \, dx}{(3+2 n) (5+2 n)}\\ &=-\frac {2 a^2 (2 B (3+n)+A (5+2 n)) \cos (e+f x) (d \sin (e+f x))^{1+n}}{d f (3+2 n) (5+2 n) \sqrt {a+a \sin (e+f x)}}-\frac {2 a B \cos (e+f x) (d \sin (e+f x))^{1+n} \sqrt {a+a \sin (e+f x)}}{d f (5+2 n)}+\frac {\left (a^3 \left (2 B \left (9+13 n+4 n^2\right )+A \left (25+30 n+8 n^2\right )\right ) \cos (e+f x)\right ) \operatorname {Subst}\left (\int \frac {(d x)^n}{\sqrt {a-a x}} \, dx,x,\sin (e+f x)\right )}{f (3+2 n) (5+2 n) \sqrt {a-a \sin (e+f x)} \sqrt {a+a \sin (e+f x)}}\\ &=-\frac {2 a^2 (2 B (3+n)+A (5+2 n)) \cos (e+f x) (d \sin (e+f x))^{1+n}}{d f (3+2 n) (5+2 n) \sqrt {a+a \sin (e+f x)}}-\frac {2 a B \cos (e+f x) (d \sin (e+f x))^{1+n} \sqrt {a+a \sin (e+f x)}}{d f (5+2 n)}+\frac {\left (a^3 \left (2 B \left (9+13 n+4 n^2\right )+A \left (25+30 n+8 n^2\right )\right ) \cos (e+f x) \sin ^{-n}(e+f x) (d \sin (e+f x))^n\right ) \operatorname {Subst}\left (\int \frac {x^n}{\sqrt {a-a x}} \, dx,x,\sin (e+f x)\right )}{f (3+2 n) (5+2 n) \sqrt {a-a \sin (e+f x)} \sqrt {a+a \sin (e+f x)}}\\ &=-\frac {2 a^2 \left (2 B \left (9+13 n+4 n^2\right )+A \left (25+30 n+8 n^2\right )\right ) \cos (e+f x) \, _2F_1\left (\frac {1}{2},-n;\frac {3}{2};1-\sin (e+f x)\right ) \sin ^{-n}(e+f x) (d \sin (e+f x))^n}{f (3+2 n) (5+2 n) \sqrt {a+a \sin (e+f x)}}-\frac {2 a^2 (2 B (3+n)+A (5+2 n)) \cos (e+f x) (d \sin (e+f x))^{1+n}}{d f (3+2 n) (5+2 n) \sqrt {a+a \sin (e+f x)}}-\frac {2 a B \cos (e+f x) (d \sin (e+f x))^{1+n} \sqrt {a+a \sin (e+f x)}}{d f (5+2 n)}\\ \end {align*}
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Mathematica [B] time = 15.40, size = 478, normalized size = 2.09 \[ \frac {2^{n+1} \tan \left (\frac {1}{2} (e+f x)\right ) \sec \left (\frac {1}{2} (e+f x)\right ) (a (\sin (e+f x)+1))^{3/2} \sin ^{-n}(e+f x) \left (\frac {\tan \left (\frac {1}{2} (e+f x)\right )}{\tan ^2\left (\frac {1}{2} (e+f x)\right )+1}\right )^n \left (\tan ^2\left (\frac {1}{2} (e+f x)\right )+1\right )^n (d \sin (e+f x))^n \left (\tan \left (\frac {1}{2} (e+f x)\right ) \left (\frac {(3 A+2 B) \, _2F_1\left (\frac {n+2}{2},n+\frac {7}{2};\frac {n+4}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )}{n+2}+\tan \left (\frac {1}{2} (e+f x)\right ) \left (\frac {2 (2 A+3 B) \, _2F_1\left (\frac {n+3}{2},n+\frac {7}{2};\frac {n+5}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )}{n+3}+\tan \left (\frac {1}{2} (e+f x)\right ) \left (\frac {2 (2 A+3 B) \, _2F_1\left (n+\frac {7}{2},\frac {n+4}{2};\frac {n+6}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )}{n+4}+\tan \left (\frac {1}{2} (e+f x)\right ) \left (\frac {(3 A+2 B) \, _2F_1\left (n+\frac {7}{2},\frac {n+5}{2};\frac {n+7}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )}{n+5}+\frac {A \tan \left (\frac {1}{2} (e+f x)\right ) \, _2F_1\left (n+\frac {7}{2},\frac {n+6}{2};\frac {n+8}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )}{n+6}\right )\right )\right )\right )+\frac {A \, _2F_1\left (\frac {n+1}{2},n+\frac {7}{2};\frac {n+3}{2};-\tan ^2\left (\frac {1}{2} (e+f x)\right )\right )}{n+1}\right )}{f \sqrt {\sec ^2\left (\frac {1}{2} (e+f x)\right )} \left (\sin \left (\frac {1}{2} (e+f x)\right )+\cos \left (\frac {1}{2} (e+f x)\right )\right )^3} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.48, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-{\left (B a \cos \left (f x + e\right )^{2} - {\left (A + B\right )} a \sin \left (f x + e\right ) - {\left (A + B\right )} a\right )} \sqrt {a \sin \left (f x + e\right ) + a} \left (d \sin \left (f x + e\right )\right )^{n}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (B \sin \left (f x + e\right ) + A\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{\frac {3}{2}} \left (d \sin \left (f x + e\right )\right )^{n}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 1.05, size = 0, normalized size = 0.00 \[ \int \left (d \sin \left (f x +e \right )\right )^{n} \left (a +a \sin \left (f x +e \right )\right )^{\frac {3}{2}} \left (A +B \sin \left (f x +e \right )\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (B \sin \left (f x + e\right ) + A\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{\frac {3}{2}} \left (d \sin \left (f x + e\right )\right )^{n}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (d\,\sin \left (e+f\,x\right )\right )}^n\,\left (A+B\,\sin \left (e+f\,x\right )\right )\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^{3/2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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